cos^3 A.sin3A+sinA.cos3A=(3/4)sin4A


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Question Number 42520 by gyugfeet last updated on 27/Aug/18

${c o s}^{3} A . s i n 3 A + s i n A . c o s 3 A = \frac{3}{4} s i n 4 A$
	Answered by tanmay.chaudhury50@gmail.com last updated on 27/Aug/18

	$c o s 3 A = \frac{4 {c o s}^{3} A - 3 c o s A}{}$ $(\frac{3 c o s A + c o s 3 A}{4}) s i n 3 A + s i n A c o s 3 A$ $\frac{3 c o s A s i n 3 A + c o s 3 A s i n 3 A + 4 s i n A c o s 3 A}{4}$ $\frac{3 (c o s A s i n 3 A + s i n A c o s 3 A) + c o s 3 A s i n 3 A + s i n A c o s 3 A}{4}$ $\frac{3 s i n 4 A + c o s 3 A (s i n 3 A + s i n A)}{4}$ $\frac{3}{4} s i n 4 A + \frac{1}{4} c o s 3 A (2 s i n 2 A c o s A)$ $p l s c h e c k t h e a u e s t i o n . . .$
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