solve for x (1/3)log(x−3)+log5−log(x−2)^2 =0


Question and Answers Forum

All Questions Topic List
None Questions
Previous in All Question Next in All Question
Previous in None Next in None
Question Number 42627 by mondodotto@gmail.com last updated on 29/Aug/18

$solve for x$ $\frac{1}{3} \log (x - 3) + \log 5 - \log {(x - 2)}^{2} = 0$
	Answered by $@ty@m last updated on 30/Aug/18

	$\log (x - 3) + 3 \log 5 - 3 \log {(x - 2)}^{2} = \log 1$ $\frac{125 (x - 3)}{{(x - 2)}^{6}} = 1$ ${(x - 2)}^{6} = 125 x - 375$ $x^{6} - 6 x^{5} . 2 + 15 x^{4} . 2^{2} - 20 x^{3} . 2^{3}$ $+ 15 x^{2} . 2^{4} - 6 x . 2^{5} + 2^{6} = 125 x - 375$ $x^{6} - 12 x^{5} + 60 x^{4} - 160 x^{3} + 240 x^{2}$ $- 317 x + 439 = 0$ $t o b e c o n t i n u e . . .$
	Answered by ajfour last updated on 30/Aug/18

	$\frac{125 (x - 3)}{{(x - 2)}^{6}} = 1$ $125 (x - 3) - {(x - 2)}^{6} = 0$ $\Rightarrow x \approx 3.008, x \approx 4.351 .$
	Commented by mondodotto@gmail.com last updated on 30/Aug/18

	$thank you sir$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum