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Question Number 42719 by jbm last updated on 01/Sep/18

Commented by Joel578 last updated on 02/Sep/18

$$\mathrm{Sophie}\mathrm{Germain}$$$$p^4+4q^4=(p^2+2pq+2q^2)(p^2-2pq+2q^2)$$$$=({(p+q)}^2+q^2)({(p-q)}^2+q^2)$$

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