How many pairs of (a, b, c, d) so that a! + b! + c! = d! which a, b, c, d ∈ positive integers .


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Question Number 42909 by naka3546 last updated on 04/Sep/18

$H o w m a n y p a i r s o f (a, b, c, d) s o t h a t$ $a! + b! + c! = d!$ $w h i c h a, b, c, d \in p o s i t i v e i n t e g e r s .$
	Answered by MJS last updated on 04/Sep/18

	$only 1 : 2! + 2! + 2! = 3!$
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