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Question Number 42910 by veerendravyas1974@gmail.com last updated on 04/Sep/18

whatshouldbesubtructedfrom(2a+8b+90)toget(−3a+7b+16)?

$${whatshouldbesubtructedfrom}\left(\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}\right){toget}\left(−\mathrm{3}{a}+\mathrm{7}{b}+\mathrm{16}\right)? \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 04/Sep/18

(2a+8b+90)−x=(−3a+7b+16)  x=(2a+8b+90)−(−3a+7b+16)  x=2a+8b+90+3a−7b−16  =5a+b+74

$$\left(\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}\right)−{x}=\left(−\mathrm{3}{a}+\mathrm{7}{b}+\mathrm{16}\right) \\ $$$${x}=\left(\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}\right)−\left(−\mathrm{3}{a}+\mathrm{7}{b}+\mathrm{16}\right) \\ $$$${x}=\mathrm{2}{a}+\mathrm{8}{b}+\mathrm{90}+\mathrm{3}{a}−\mathrm{7}{b}−\mathrm{16} \\ $$$$=\mathrm{5}{a}+{b}+\mathrm{74} \\ $$

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