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Question Number 43128 by Cheyboy last updated on 07/Sep/18

Commented by Cheyboy last updated on 07/Sep/18

$$Findthearea$$

Commented by ajfour last updated on 07/Sep/18

$$SeeQ.43131forapossiblesolution.$$

Commented by Cheyboy last updated on 07/Sep/18

$$Buttheworkingisnotshown$$

Commented by ajfour last updated on 07/Sep/18

$$insometimeishallpost.$$

Commented by Cheyboy last updated on 07/Sep/18

$$Oksirthankyou$$

Answered by behi83417@gmail.com last updated on 07/Sep/18

$$x^2=6^2+7^2-2\times 6\times 7\times cos\alpha$$$$x^2=8^2+{11}^2-2\times 8\times 11\times cos\beta$$$$36+49-84cos\alpha =64+121-176cos\beta$$$$(176+84)cos\alpha =85-185$$$$cos\alpha =\frac{-100}{260}\Rightarrow \alpha =112.{62}^{\bullet }$$$$S=\frac{1}{2}(6\times 7+8\times 11).sin112.62=$$$$\text{You can't use 'macro parameter character \#' in math mode}$$

Commented by ajfour last updated on 07/Sep/18

$$if\alpha =\beta ({isn}^{\prime }titso,Sir?)$$

Commented by behi83417@gmail.com last updated on 07/Sep/18

$$nosir.[\alpha +\beta =\pi \Rightarrow sin\alpha =sin\beta ]$$

Commented by ajfour last updated on 07/Sep/18

$$howcanweknowandbesure?$$

Commented by MJS last updated on 07/Sep/18

$$\mathrm{we}\mathrm{cannot}$$

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