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Question Number 43159 by MASANJA J last updated on 07/Sep/18
Answered by alex041103 last updated on 08/Sep/18
For∫dxx+15:∫dxx+15=∫d(x+15)x+15=∫u−1/2du==2u1/2+C=2x+15+CFor∫ln(x)dx(1+x)2seeQ.43191
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