Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 43205 by Tawa1 last updated on 08/Sep/18

Answered by $@ty@m last updated on 08/Sep/18

$$\because \mathrm{\angle }SRQ=\mathrm{\angle }RTS\left(alternatesegmenttheorem\right)$$$$\therefore \mathrm{\angle }SRQ={28}^{\mathrm{o}}$$$$Wehave$$$$\mathrm{\angle }VRM+\mathrm{\angle }VRS+\mathrm{\angle }SRQ={180}^{\mathrm{o}}$$$$\Rightarrow {46}^{\mathrm{o}}+\mathrm{\angle }VRS+{28}^{\mathrm{o}}={180}^{\mathrm{o}}$$$$\Rightarrow \mathrm{\angle }VRS+{106}^{\mathrm{o}}={180}^{\mathrm{o}}...\left(1\right)$$$$Weknowthatoppositeanglesof$$$$acyclicquadrilateralaresupplementary.$$$$\therefore \mathrm{\angle }VRS+\mathrm{\angle }VUS={180}^{\mathrm{o}}....\left(2\right)$$$$From\left(1\right)\mathrm{\&}\left(2\right),$$$$weget$$$$\mathrm{\angle }VUS={106}^{\mathrm{o}}Ans.$$

Commented by Tawa1 last updated on 08/Sep/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com