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Question Number 43338 by ajfour last updated on 09/Sep/18

Commented by ajfour last updated on 10/Sep/18

$$Find\mathit{r}intermsof\mathit{R}$$$$\left(inthecaseofcircles\right).$$

Answered by ajfour last updated on 10/Sep/18

$$$$$$(R-r)\cos \frac{\pi }{6}=\frac{R}{2}$$$$\Rightarrow r=R(1-\frac{1}{\sqrt{3}}).$$

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