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Question Number 43343 by pieroo last updated on 10/Sep/18
howmanyoddnumbersgreaterthan60000canbemadefromthedigits5,6,7,8,9,0ifnonumbercontainsanydigitmorethanonce?
Answered by tanmay.chaudhury50@gmail.com last updated on 10/Sep/18
−5−4−3−2−1digitsare5,6,7,8,9,0(sixnosofdigit)numbersgreaterthan60,000...the5thplacecanbefilledby(6,7,8,9)numbersareoddso1stplacecanbefilled(5,7,9)1)−65−4−3−2−515thplacefilledby6and1stplaceby54thplacecanbefilledbyanydigitoutof(7,8,9,0)so4ways3rdplacecanbefilledbyanyremainingthreedigitso3ways2ndplacecanbefilledbyanyremainingtwodigitso2waysThusthenumberswhose1stplaceis5and5thplaceis6thatmeansgreaterthan60000butoddare4×3×2=24−65−×4−×3−×2−51→24−65−×4−×3−×2−71→24−65−×4−×3−×2−91−24thus24×3=72−75−×4−×3−×2−51→24−75−×4−×3−×2−91→24−85−×4−×3−×2−51→24−85−×4−×3−×2−71→24−85−×4−×3−×2−91→24−95−×4−×3−×2−51→24−95−×4−×3−×2−71→245thplace6→24×3=725thplacd7→24×2=485thplace8→24×3=725thplace9→24×2=48total=72+48+72+48=240
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