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Question Number 43344 by peter frank last updated on 10/Sep/18

$$\mathrm{The}\mathrm{number}1,2,3,...,n\mathrm{are}\mathrm{arranged}$$ $$\mathrm{in}\mathrm{a}\mathrm{random}\mathrm{order}.\mathrm{The}\mathrm{probability}$$ $$\mathrm{that}\mathrm{the}\mathrm{digits}1,2,3,...,k(k>n)\mathrm{appears}$$ $$\mathrm{as}\mathrm{neighbours}\mathrm{is}$$

Commented byMrW3 last updated on 10/Sep/18

$$k<n$$ $$\frac{(n-k+1)!k!}{n!}$$

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