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Question Number 43537 by abdo.msup.com last updated on 11/Sep/18

$$let{S}_n=\sum _{k=1}^n\frac{e^{\frac{k}{n}}}{n}$$$$find{lim}_{n\to +\mathrm{\infty }}{S}_n$$

Commented by maxmathsup by imad last updated on 29/Sep/18

$${lim}_{n\to +\mathrm{\infty }}{S}_n={lim}_{n\to +\mathrm{\infty }}\frac{1}{n}\sum _{k=1}^n{e}^{\frac{k}{n}}={\int }_0^1{e}^{x}dx=e-1.$$

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