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Question Number 43544 by behi83417@gmail.com last updated on 11/Sep/18

Answered by MJS last updated on 12/Sep/18

x=z−(1/3)  z^3 −(1/3)z+(2/(27))−((√2)/(10))=0  trigonometric solution method  z_k =2(√(−(p/3)))sin(((2πk)/3)+(1/3)arcsin(((9q)/(2p^2 ))(√(−(p/3)))))  x_k =z_k −(1/3)  x_1 ≈.326514  x_2 ≈−.745626  x_3 ≈−.580888

x=z13z313z+227210=0trigonometricsolutionmethodzk=2p3sin(2πk3+13arcsin(9q2p2p3))xk=zk13x1.326514x2.745626x3.580888

Commented by behi83417@gmail.com last updated on 12/Sep/18

thanks in advance sir.

thanksinadvancesir.

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