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Question Number 43544 by behi83417@gmail.com last updated on 11/Sep/18
Answered by MJS last updated on 12/Sep/18
x=z−13z3−13z+227−210=0trigonometricsolutionmethodzk=2−p3sin(2πk3+13arcsin(9q2p2−p3))xk=zk−13x1≈.326514x2≈−.745626x3≈−.580888
Commented by behi83417@gmail.com last updated on 12/Sep/18
thanksinadvancesir.
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