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Question Number 43748 by naka3546 last updated on 15/Sep/18

Answered by tanmay.chaudhury50@gmail.com last updated on 15/Sep/18

$$f\left(x\right)=3x^3+x-1$$$$f\left(0\right)=-ve$$$$f\left(1\right)=+ve$$$$f(0.5)=-ve$$$$f(0.6)=+ve$$$$so0.6>x>0.5$$$$f(0.55)>+ve$$$$f(0.53)<-ve$$$$x\approx 0.54$$$$6x^3-x^2-3x+2010$$$$6{(0.54)}^3-{(0.54)}^2-3(0.54)+2010$$$$\approx 2009$$

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