Probably if x^n =Am ((a/b)π), x=e^(((2k+a)/(bn))iπ) about 0<(k∈N∪{0})<(n∈N) and b≠0. p.s. Am (0°)=1, Am (90°)=i etc., and s°=(π/(180))s rad(ians)=(π/(180))s.


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Question Number 43757 by Rauny last updated on 15/Sep/18
$Probably if x^n =Am ((a/b)π), x=e^(((2k+a)/(bn))iπ) about 0<(k∈N∪{0})<(n∈N) and b≠0. p.s. Am (0°)=1, Am (90°)=i etc., and s°=(π/(180))s rad(ians)=(π/(180))s.$
$Probably if x^{n} = A m (\frac{a}{b} π), x = e^{\frac{2 k + a}{b n} i π}$ $about 0 < (k \in N \cup {0}) < (n \in N) and b \neq 0 .$ $p . s . A m (0 °) = 1, A m (90 °) = i etc .,$ $and s ° = \frac{π}{180} s rad (ians) = \frac{π}{180} s .$
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