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Question Number 43789 by Junaid555 last updated on 15/Sep/18

 plz solve it for me i am learning      (((81)/(125)))^(1/3)

plzsolveitformeiamlearning811253

Answered by MJS last updated on 15/Sep/18

((a/b))^(1/n) =((a)^(1/n) /(b)^(1/n) )     ((a×b))^(1/n) =(a)^(1/n) ×(b)^(1/n)   (c^n )^(1/n) =c  there are some exceptions but at this level  it′s good to remember these    (((81)/(125)))^(1/3) =(((81))^(1/3) /((125))^(1/3) )=(((3×3×3×3))^(1/3) /((5×5×5))^(1/3) )=(((3^3 ×3))^(1/3) /(5^3 )^(1/3) )=  =(((3^3 )^(1/3) ×(3)^(1/3) )/5)=(3/5)(3)^(1/3)

abn=anbna×bn=an×bncnn=ctherearesomeexceptionsbutatthislevelitsgoodtorememberthese811253=8131253=3×3×3×335×5×53=33×33533==333×335=3533

Commented by Junaid555 last updated on 15/Sep/18

Thank you very much

Thankyouverymuch

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