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Question Number 43824 by Necxx last updated on 15/Sep/18

Answered by MJS last updated on 16/Sep/18

$$\left(\frac{1}{2}\right)!=\frac{\sqrt{\pi }}{2}$$$$\left(\frac{1}{2}\right)!+\left(\frac{1}{2}\right)!=\sqrt{\pi }$$$$\left(\mathrm{A}\right)1!=1$$$$\left(\mathrm{B}\right)\sin 45°=\frac{\sqrt{2}}{2}$$$$\left(\mathrm{C}\right)\sqrt{\arccos -1}=\sqrt{\pi }$$$$\left(\mathrm{D}\right)\sqrt{\arcsin 1}=\frac{\sqrt{2\pi }}{2}$$$$\Rightarrow \left(\mathrm{C}\right)\mathrm{is}\mathrm{the}\mathrm{right}\mathrm{answer}$$

Commented by Necxx last updated on 16/Sep/18

$$thankyousir$$

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