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Question Number 44020 by rahul 19 last updated on 20/Sep/18

Answered by tanmay.chaudhury50@gmail.com last updated on 20/Sep/18

$$\overrightarrow{a}.\overrightarrow{d}=\mid \overrightarrow{a}\mid cos{\theta }_1\overrightarrow{b}.\overrightarrow{d}=\mid \overrightarrow{b}\mid cos{\theta }_2\overrightarrow{c}.\overrightarrow{d}=\mid \overrightarrow{c}\mid cos{\theta }_3$$$$acos{\theta }_{1}bcos{\theta }_{2}ccos{\theta }_{3}where\mid \overrightarrow{a}\mid =a$$$$\mid \overrightarrow{b}\mid =b\mid \overrightarrow{c}\mid =c$$$$sogivenexpressionis$$$$\mid acos{\theta }_1\left(\overrightarrow{b}\times \overrightarrow{c}\right)+bcos{\theta }_2\left(\overrightarrow{c}\times \overrightarrow{a}\right)+ccos{\theta }_3\left(\overrightarrow{a}\times \overrightarrow{b}\right)\mid$$$$isindependentof\overrightarrow{d}$$

Commented by rahul 19 last updated on 20/Sep/18

$$Oksir,\mathrm{thanks}.$$

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