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Question Number 44034 by Dilshad786 last updated on 20/Sep/18

$$\mathrm{Let}{I}_1=\underset{1}{\stackrel{2}{\int }}\frac{1}{\sqrt{1+x^2}}dx\mathrm{and}{I}_2=\underset{1}{\stackrel{2}{\int }}\frac{1}{x}dx.$$$$\mathrm{Then}$$

Commented by maxmathsup by imad last updated on 20/Sep/18

$$I_1=[ln{(x+\sqrt{1+x^2}]}_1^2=ln(2+\sqrt{5})-ln(1+\sqrt{2})and$$$$I_2={[ln\mid x\mid ]}_1^2=ln\left(2\right).$$

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