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Question Number 44062 by peter frank last updated on 20/Sep/18

	Answered by MJS last updated on 21/Sep/18

	$roots r_{1}, r_{2} \Rightarrow (x - r_{1}) (x - r_{2}) = 0 \Rightarrow x^{2} - (r_{1} + r_{2}) x + r_{1} r_{2} = 0$ $in this case$ $r_{1} = 2 - \sqrt{3}, r_{2} = 2 + \sqrt{3}$ $(x - 2 + \sqrt{3}) (x - 2 - \sqrt{3}) = 0 \Rightarrow$ $\Rightarrow x^{2} - 4 x + 1 = 0$
	Commented by $@ty@m last updated on 21/Sep/18

	$G e n e r a l f o r m u l a :$ $x^{2} - (r_{1} + r_{2}) x + r_{1} . r_{2} = 0$
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