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Question Number 44212 by 12344 last updated on 23/Sep/18

solve for x if.  3^2 −1=x^3

$$\mathrm{solve}\:\mathrm{for}\:\mathrm{x}\:\mathrm{if}. \\ $$$$\mathrm{3}^{\mathrm{2}} −\mathrm{1}=\mathrm{x}^{\mathrm{3}} \\ $$

Answered by Joel578 last updated on 23/Sep/18

9 − 1 = x^3   x^3  = 8  x = (8)^(1/3)  = 2

$$\mathrm{9}\:−\:\mathrm{1}\:=\:{x}^{\mathrm{3}} \\ $$$${x}^{\mathrm{3}} \:=\:\mathrm{8} \\ $$$${x}\:=\:\sqrt[{\mathrm{3}}]{\mathrm{8}}\:=\:\mathrm{2} \\ $$

Commented by MJS last updated on 23/Sep/18

x^3 −8=0  (x−2)(x^2 +2x+4)=0  x_1 =2  x_2 =−1−i(√3)  x_3 =−1+i(√3)

$${x}^{\mathrm{3}} −\mathrm{8}=\mathrm{0} \\ $$$$\left({x}−\mathrm{2}\right)\left({x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{4}\right)=\mathrm{0} \\ $$$${x}_{\mathrm{1}} =\mathrm{2} \\ $$$${x}_{\mathrm{2}} =−\mathrm{1}−\mathrm{i}\sqrt{\mathrm{3}} \\ $$$${x}_{\mathrm{3}} =−\mathrm{1}+\mathrm{i}\sqrt{\mathrm{3}} \\ $$

Commented by 12344 last updated on 23/Sep/18

wrong process

$$\mathrm{wrong}\:\mathrm{process} \\ $$

Commented by 12344 last updated on 23/Sep/18

wrong process

$$\mathrm{wrong}\:\mathrm{process} \\ $$

Commented by 12344 last updated on 23/Sep/18

wrong process

$$\mathrm{wrong}\:\mathrm{process} \\ $$

Commented by 12344 last updated on 23/Sep/18

big thanks to you sir.  butI need the answer for the other question.PLEASE.

$$\mathrm{big}\:\mathrm{thanks}\:\mathrm{to}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{butI}\:\mathrm{need}\:\mathrm{the}\:\mathrm{answer}\:\mathrm{for}\:\mathrm{the}\:\mathrm{other}\:\mathrm{question}.\mathrm{PLEASE}. \\ $$

Commented by 12344 last updated on 23/Sep/18

answer the other one for me please sir.

$$\mathrm{answer}\:\mathrm{the}\:\mathrm{other}\:\mathrm{one}\:\mathrm{for}\:\mathrm{me}\:\mathrm{please}\:\mathrm{sir}. \\ $$

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