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Question Number 44212 by 12344 last updated on 23/Sep/18

$$\mathrm{solve}\mathrm{for}\mathrm{x}\mathrm{if}.$$$$3^2-1={\mathrm{x}}^3$$

Answered by Joel578 last updated on 23/Sep/18

$$9-1=x^3$$$$x^3=8$$$$x=\sqrt[3]{8}=2$$

Commented by MJS last updated on 23/Sep/18

$$x^3-8=0$$$$(x-2)(x^2+2x+4)=0$$$$x_1=2$$$$x_2=-1-\mathrm{i}\sqrt{3}$$$$x_3=-1+\mathrm{i}\sqrt{3}$$

Commented by 12344 last updated on 23/Sep/18

$$\mathrm{wrong}\mathrm{process}$$

Commented by 12344 last updated on 23/Sep/18

$$\mathrm{wrong}\mathrm{process}$$

Commented by 12344 last updated on 23/Sep/18

$$\mathrm{wrong}\mathrm{process}$$

Commented by 12344 last updated on 23/Sep/18

$$\mathrm{big}\mathrm{thanks}\mathrm{to}\mathrm{you}\mathrm{sir}.$$$$\mathrm{butI}\mathrm{need}\mathrm{the}\mathrm{answer}\mathrm{for}\mathrm{the}\mathrm{other}\mathrm{question}.\mathrm{PLEASE}.$$

Commented by 12344 last updated on 23/Sep/18

$$\mathrm{answer}\mathrm{the}\mathrm{other}\mathrm{one}\mathrm{for}\mathrm{me}\mathrm{please}\mathrm{sir}.$$

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