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Question Number 44222 by Necxx last updated on 23/Sep/18

$$Amanborrowedxat5\mathrm{\%}perannum$$$$simpleinterest.Hepaid198000$$$$after2years.Calculate{}_{}$$$$a)thevalueofx$$$$b)simpleinterest$$

Answered by olj55336@awsoo.com last updated on 24/Sep/18

$$taken100+5+5.25payfullamount$$$$198000/110.25\times 100=179591.84$$$$$$

Commented by 12344 last updated on 24/Sep/18

$$\mathrm{no}\mathrm{no}\mathrm{no}$$

Answered by 12344 last updated on 24/Sep/18

$$\mathrm{I}=\frac{\mathrm{PRT}}{100}$$$$\mathrm{cross}\mathrm{multiply}$$$$\mathrm{I}\times 100=\mathrm{PRT}$$$$100\mathrm{I}=\mathrm{PRT}$$$$\mathrm{where}\mathrm{P}=x.\mathrm{R}=5.\mathrm{T}=2.\mathrm{I}=?$$$$100\mathrm{I}=x\times 5\times 2$$$$100\mathrm{I}=\mathrm{x}\times 10$$$$100\mathrm{I}=10x$$$$\frac{100\mathrm{I}}{10}=\frac{10x}{10}$$$$10\mathrm{I}=x...............\left(1\right)$$$$B\mathrm{UT}$$$$x+\mathrm{I}=198000.........\left(2\right)$$$$\mathrm{substitute}\left(1\right)\mathrm{into}\left(2\right)$$$$10\mathrm{I}+\mathrm{I}=198000$$$$11\mathrm{I}=198000$$$$\frac{11\mathrm{I}}{11}=\frac{198000}{11}$$$$\mathrm{I}=18000$$$$\mathrm{bu}t$$$$10\mathrm{I}=x$$$$10\left(18000\right)=x$$$$180000=x$$$$therefore$$$$\mathrm{a})x=180000$$$$\mathrm{b})\mathrm{simple}\mathrm{interest}\left(\mathrm{I}\right)=18000$$

Commented by Necxx last updated on 24/Sep/18

$$Thankyousomuchsir$$

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