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Question Number 44306 by abdo.msup.com last updated on 26/Sep/18
find∫dt(t+1)t+tt+12)calculate∫13dt(t+1)t+tt+1
Commented by maxmathsup by imad last updated on 29/Sep/18
I=∫dttt+1(t+1+t)=∫t+1−ttt+1dt=∫dtt−∫dtt+1=2t−2t+1+c.
∫13dt(t+1)t+tt+1=[2t−2t+1]13=23−4−2+22=22+23−6.
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