Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 44397 by Necxx last updated on 28/Sep/18

If x is nearly equal to 1 then ((mx^m −nx^n )/(m−n))=

Ifxisnearlyequalto1thenmxm−nxnm−n=

Commented by MrW3 last updated on 28/Sep/18

if x≈1 ⇒x^m ≈x^n ≈1 ((mx^m −nx^n )/(m−n))≈((m−n)/(m−n))=1

ifx≈1⇒xm≈xn≈1mxm−nxnm−n≈m−nm−n=1

Commented by Necxx last updated on 28/Sep/18

The options are a) x^(m+n) b)x^(m−n) c)x^m d)x^n I also got 1 but couldnt see it in option

Theoptionsarea)xm+nb)xm−nc)xmd)xnIalsogot1butcouldntseeitinoption

Commented by MrW3 last updated on 28/Sep/18

all these options are also ≈1

alltheseoptionsarealso≈1

Commented by math khazana by abdo last updated on 29/Sep/18

changement x =1+ξ give ((mx^m −nx^n )/(m−n)) =((m(1+ξ)^m −n(1+ξ)^n )/(m−n)) =A(x) x→1 ⇒ξ→0 so (1+ξ)^m ∼1+mξ and (1+ξ)^n ∼1+nξ ⇒A(x) ∼ ((m(1+mξ)−n(1+nξ))/(m−n)) = 1 +(m+n)ξ →1 (ξ→0) ⇒ lim_(x→1) A(x)) =1 .

changementx=1+ξgivemxm−nxnm−n=m(1+ξ)m−n(1+ξ)nm−n=A(x)x→1⇒ξ→0so(1+ξ)m∼1+mξand(1+ξ)n∼1+nξ⇒A(x)∼m(1+mξ)−n(1+nξ)m−n=1+(m+n)ξ→1(ξ→0)⇒limx→1A(x))=1.

Answered by ajfour last updated on 28/Sep/18

= ((m(1+mh)−n(1+nh))/(m−n)) = 1 .

=m(1+mh)−n(1+nh)m−n=1.

Answered by tanmay.chaudhury50@gmail.com last updated on 28/Sep/18

((mx^m −nx^m +nx^m −nx^n )/(m−n)) =((x^m (m−n)+nx^n (x^(m−n) −1))/(m−n)) =x^m +((x^n (x^(m−n) −1))/((m/n)−1)) x^(m−n) ≈1 =x^m

mxm−nxm+nxm−nxnm−n=xm(m−n)+nxn(xm−n−1)m−n=xm+xn(xm−n−1)mn−1xm−n≈1=xm

Commented by Necxx last updated on 28/Sep/18

Thats true... I′m clear now

Thatstrue...I′mclearnow

Terms of Service

Privacy Policy

Contact: info@tinkutara.com