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Question Number 44441 by Tawa1 last updated on 29/Sep/18

Answered by tanmay.chaudhury50@gmail.com last updated on 29/Sep/18

$$\underset{t\to 0}{\lim }\frac{e^{-5t}-1}{-5t}\times -5$$$$=1\times -5=-5$$$$\underset{t\to 0}{\lim }\frac{t^{11}}{t^{11}(t-1)}=\underset{t\to 0}{\lim }\frac{1}{t-1}=-1$$$$\underset{t\to 0}{\lim }\frac{1}{11+t}=\frac{1}{11}$$

Commented by Tawa1 last updated on 29/Sep/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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