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Question Number 44636 by Raj Singh last updated on 02/Oct/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 02/Oct/18

	$j o i n o B a n d O C$ $△ O A B a n d O A C$ $1) O B = O C (r a d i u s)$ $2) ∠ A B O = ∠ A C O = 90^{o}$ $3) O A c o m m o n$ $s o △ O A B c o n g u r e n t △ O A C$ $s o$ $∠ O A B = ∠ O A C$ $A B = A C$ $l e t B C i n t e r z e c t O A a t p o i n t P$ $i n △ A P B a n d △ A P C$ $A B = A C$ $A P c o m m o n$ $∠ O A B = ∠ O A C$ $s o △ A P B c o n g u r e n t △ A P C$ $s o ∠ A P B = ∠ A P C = α$ $α + α = 180^{o}$ $α = 90^{o} h e n c e B C ⊥ O A$ $B P = P C$
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