Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 44808 by jasno91 last updated on 05/Oct/18

Commented by Kunal12588 last updated on 05/Oct/18

read some books

$${read}\:{some}\:{books} \\ $$

Answered by Kunal12588 last updated on 05/Oct/18

1) (82−18)(82+18)=6400  2) (128−72)(128+72)=56×200=11200  3)200^2 −3^2 =40000−9=39991  4)(((198−102)(198+102))/(96))=300  5)(15−0.3)(15+0.3)=225−0.09=224.91  6)(8.63+1.37)(8.63−1.37)=72.6

$$\left.\mathrm{1}\right)\:\left(\mathrm{82}−\mathrm{18}\right)\left(\mathrm{82}+\mathrm{18}\right)=\mathrm{6400} \\ $$$$\left.\mathrm{2}\right)\:\left(\mathrm{128}−\mathrm{72}\right)\left(\mathrm{128}+\mathrm{72}\right)=\mathrm{56}×\mathrm{200}=\mathrm{11200} \\ $$$$\left.\mathrm{3}\right)\mathrm{200}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} =\mathrm{40000}−\mathrm{9}=\mathrm{39991} \\ $$$$\left.\mathrm{4}\right)\frac{\left(\mathrm{198}−\mathrm{102}\right)\left(\mathrm{198}+\mathrm{102}\right)}{\mathrm{96}}=\mathrm{300} \\ $$$$\left.\mathrm{5}\right)\left(\mathrm{15}−\mathrm{0}.\mathrm{3}\right)\left(\mathrm{15}+\mathrm{0}.\mathrm{3}\right)=\mathrm{225}−\mathrm{0}.\mathrm{09}=\mathrm{224}.\mathrm{91} \\ $$$$\left.\mathrm{6}\right)\left(\mathrm{8}.\mathrm{63}+\mathrm{1}.\mathrm{37}\right)\left(\mathrm{8}.\mathrm{63}−\mathrm{1}.\mathrm{37}\right)=\mathrm{72}.\mathrm{6} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com