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Question Number 44898 by ajfour last updated on 06/Oct/18
Ifx4+px3+qx2+rx+5=0hasfourrealroots,thenfindtheminimumvalueofpr.
Commented by MJS last updated on 06/Oct/18
letmetry...
Answered by ajfour last updated on 06/Oct/18
x1x2x3x4=5Σx1x2x3=−rx1+x2+x3+x4=−ppr=5(1x4+1x2+1x3+1x4)Σx1>5×4xc×4xc(=80).Hencemin(pr)=80.
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