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Question Number 44928 by rahul 19 last updated on 06/Oct/18

Commented by rahul 19 last updated on 06/Oct/18

$$a)Maximumcompressioninthe$$$$springis\frac{w_o}{2}\sqrt{\frac{{mr}^2}{k}}.$$$$b)Angularvelocityoflowerdiscafter$$$$springhasrelaxedis{w}_o.$$$$c)None.$$

Commented by MrW3 last updated on 06/Oct/18

$$a)$$$$max.compressioninspring=d$$$$\frac{1}{2}{kd}^2=\frac{1}{2}\times \frac{{mr}^2}{2}\times {\omega }_0^2$$$$\Rightarrow d={\omega }_0\sqrt{\frac{{mr}^2}{2k}}$$$$\Rightarrow optiona)iswrong$$$$b)$$$$afterthespringhasrelaxedagainboth$$$$discshavethesameangularvelocity\omega$$$$2\times \frac{1}{2}\times \frac{{mr}^2}{2}\times {\omega }^2=\frac{1}{2}\times \frac{{mr}^2}{2}\times {\omega }_0^2$$$$\Rightarrow \omega =\frac{{\omega }_0}{\sqrt{2}}$$$$\Rightarrow optionb)iswrong$$$$$$$$\Rightarrow answerisc)$$

Commented by rahul 19 last updated on 06/Oct/18

$$thankssir!$$

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