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Question Number 44967 by peter frank last updated on 06/Oct/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 07/Oct/18

	$T h e l a n g u a g e o f p r o b l e m i s n o t c l e a r . . .$ $p l s c l a r i f y t h e f u n c t i o n o f p i p e P a n d i t s r a t e$ $p i p e Q a n d r a t e a n d p i p e R a n d r a t e . . .$ $b y t h e w a y . . i f t w o p i p e i s p r e s e n t o n e f i l l t h e t a n k$ $a n o t h e r e m p t y t h e t a n k$ $t h e s o l u t i o n g i v e n b e l o w$ $f i l l i n g p i p e f i l l t a n k \frac{1}{6} / h o u r$ $e m p t y p i p e e m p t y t a n k \frac{1}{12} / h o u r$ $i n 1 h o u r t a n k g e t s f i l l e d = \frac{1}{6} - \frac{1}{12} = \frac{2 - 1}{12} = \frac{1}{12} p o r t i o n$ $i n 4 h o u r s i t g e t f i l l e d = \frac{4}{12} = \frac{3}{4} p o r t i o n$ $n o w p i p e w h i c h e m p t y t h e t a n k s w i t c h e d o f f$ $r e m a i n i n g p o r t i o n o f t a n k t o f i l l = 1 - \frac{3}{4} = \frac{1}{4}$ $s o t i m e t a k e n t o f i l l \frac{1}{4} p o r t i o n = \frac{1}{4} \times 6 = \frac{3}{2} h o u r s$ $s o t o t a l t i m e t o f i l l t h e t a n k = 4 + \frac{3}{2} = \frac{11}{2} h o u r s$ $n o m e n t i o n o f p i p e P, Q a n d R i n p r o b l e m$ $s o p l s r e p o s t t h e p r o b l e m w i t h c l e a r l a n g u a g e$
	Commented by peter frank last updated on 07/Oct/18

	$t hanks sir for correcton . i really appriciate your effort$
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