Math Question and Answers


Question and Answers Forum

All Questions Topic List
Heat and Theromdynamics Questions
Previous in All Question Next in All Question
Previous in Heat and Theromdynamics Next in Heat and Theromdynamics
Question Number 45125 by Necxx last updated on 09/Oct/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 09/Oct/18

	$a t t e m p a r a t u r e T c u b e e d g e = L$ $a t t e m p T + d T c u b e e d g e = L + d L$ $s u r f a c e a r e a a t t e p m T i s L^{2}$ $a t t e m p T + d T s u r f a c e a r e a = {(L + d L)}^{2}$ $g i v e n α = \frac{d L}{L \times d T} d L = α L d T$ $A = L^{2}$ $A + d A = {(L + d L)}^{2} = L^{2} + 2 L d L + {(d L)}^{2}$ $A + d A \approx L^{2} + 2 L d L$ $d A = 2 L d L$ $d A = 2 L \times α L d T = 2 α L^{2} d T$ $h e r e d T = 1$ $s o d A = 2 α L^{2}$ $★ ★ ★ f o r t o t a l s u r f a c e a r e a . . .$ $S = 6 L^{2}$ $S + d S = 6 {(L + d L)}^{2} \approx 6 (L^{2} + 2 L d L)$ $d S = 12 L d L$ $d S = 12 L \times α L d T = 12 α L^{2} d T$ $h e r e d T = 1$ $d S = 12 α L^{2}$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum