Question and Answers Forum

All Questions      Topic List

Integration Questions

Previous in All Question      Next in All Question      

Previous in Integration      Next in Integration      

Question Number 45165 by Tinkutara last updated on 09/Oct/18

Answered by tanmay.chaudhury50@gmail.com last updated on 10/Oct/18

$$\int \frac{sin5x(2cos\frac{15x}{2}.cos\frac{3x}{2})}{sin5x-sin10x}dx$$$$\int \frac{2sin\frac{5x}{2}cos\frac{5x}{2}\left(2cos\frac{15x}{2}cos\frac{3x}{2}\right)}{-2cos\frac{15x}{2}.sin\frac{5x}{2}}dx$$$$=-\int 2cos\frac{5x}{2}.cos\frac{3x}{2}dx$$$$=-\int cos4x+cosxdx$$$$=-(\frac{sin4x}{4}+sinx)+c$$$$k=4$$$$$$

Commented by Tinkutara last updated on 10/Oct/18

Thank you very much Sir! I got the answer. ��������

Commented by tanmay.chaudhury50@gmail.com last updated on 11/Oct/18

$$mostwelcome...$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com