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Question Number 45281 by peter frank last updated on 11/Oct/18

Commented by math1967 last updated on 11/Oct/18

$$plschq.q.no1$$

Commented by peter frank last updated on 11/Oct/18

$$\mathrm{i}\mathrm{forgot}\mathrm{this}‘‘=0^{″}\mathrm{very}\mathrm{sorry}$$$$$$

Answered by math1967 last updated on 11/Oct/18

$$2)siny=2sinx$$$${sin}^{2}y=4{sin}^{2}x$$$$\therefore 4-{sin}^{2}y=4-4{sin}^{2}x$$$$3+{cos}^{2}y=4{cos}^{2}x$$$$nowsiny=2sinx$$$$cosy\frac{dy}{dx}=2cosx$$$${\left(\frac{dy}{dx}\right)}^2=\frac{4{cos}^{2}x}{{cos}^{2}y}=\frac{3+{cos}^{2}y}{{cos}^{2}y}=3{sec}^{2}y+1$$$$$$$$$$

Commented by peter frank last updated on 11/Oct/18

$$\mathrm{thank}\mathrm{you}\mathrm{sir}.\mathrm{pls}\mathrm{help}\mathrm{no}1$$

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