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Question Number 45539 by rahul 19 last updated on 14/Oct/18

Commented by rahul 19 last updated on 14/Oct/18

$A n s : \frac{I π R^{2}}{c} w h e r e c = s p e e d o f l i g h t .$
Commented by tanmay.chaudhury50@gmail.com last updated on 14/Oct/18

	Answered by tanmay.chaudhury50@gmail.com last updated on 14/Oct/18

	$i n t e n s i t y = I (w / m^{2})$ $p r o j e c t e d e r o s s s e c t i o n a l a r e a o f l i g h t b e a m t h a t s t r i k e s p h e r e i s$ $π R^{2}$ $(p o w e r = f o r c e \times v e l o c i t y$ $f o r c e = \frac{p o w e r}{v e l o c i t y} = \frac{I}{c} p e r u n i t a r e a$ $s o f o r c e e x e r t e d b y p h o t o n s c o m i n g t h r o u v h$ $p r o j e c t e d c r o s s s e c t i o n a l a r e a π R^{2} i s$ $F_{B} = \frac{I}{c} \times π R^{2} (f o r p e r f e c t l y b l a c k b o d y)$ $F_{R} = \frac{I}{c} \times π R^{2} \times 2 (f o r r e f l e c t i n g s u r f a c e)$ $f o r b e t t e r u n d e r s t s n d i n g v i s i t y o u t u b e v i d e o . . .$
	Commented by rahul 19 last updated on 14/Oct/18
	Thank you so much sir ! ☺️��
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