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Question Number 45561 by Sanjarbek last updated on 14/Oct/18

Commented by tanmay.chaudhury50@gmail.com last updated on 14/Oct/18

$$x=sin\theta dx=cos\theta d\theta$$$$\int \frac{cos\theta d\theta }{\sqrt{cos\theta }}$$$$\int \sqrt{cos\theta }d\theta$$$$wait...$$

Commented by arvinddayama01@gmail.com last updated on 14/Oct/18

$$x=cos\theta$$$$dx=-sin\theta d\theta$$$$-\int \frac{sin\theta d\theta }{\sqrt{sin\theta }}$$$$-\int \sqrt{sin\theta }d\theta ...$$

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