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Question Number 45609 by peter frank last updated on 14/Oct/18

Commented by MrW3 last updated on 14/Oct/18

$$\frac{b}{\sin B}=\frac{a}{\sin A}=\frac{a}{\sin (B+C)}$$$$\Rightarrow b=a\frac{\sin B}{\sin (B+C)}$$$$Area=\frac{1}{2}ab\sin C=\frac{a^2\sin B\sin C}{2\sin (B+C)}$$$$$$$$butthishasnothingtodowiths.$$

Commented by peter frank last updated on 14/Oct/18

$$\mathrm{thanks}$$

Commented by peter frank last updated on 14/Oct/18

$$\mathrm{help}\mathrm{sir}\mathrm{Qn}45514$$

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