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Question Number 45794 by Tawa1 last updated on 16/Oct/18

Answered by MJS last updated on 16/Oct/18

$$a\ast c=b\Rightarrow b\ast c^{-1}=a\Rightarrow c^{-1}=b$$$$b\ast c=d\Rightarrow d\ast c^{-1}=b\Rightarrow c^{-1}=b$$$$c\ast c=a\Rightarrow a\ast c^{-1}=c\Rightarrow c^{-1}=b$$$$d\ast c=c\Rightarrow c\ast c^{-1}=d\Rightarrow c^{-1}=b$$$$\Rightarrow c^{-1}=b$$

Commented by Tawa1 last updated on 16/Oct/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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