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Question Number 45930 by Tawa1 last updated on 18/Oct/18

Answered by MJS last updated on 19/Oct/18

$$\mathrm{for}\mathrm{any}\mathrm{shape}$$$$\mathrm{length}(\mathrm{or}\mathrm{radius},\mathrm{height},\mathrm{width}...)\times k$$$$\Rightarrow \mathrm{area}\times k^2$$$$\Rightarrow \mathrm{volume}\times k^3$$$$l\times k\Rightarrow a\times k^2,v\times k^3$$$$a\times k\Rightarrow l\times \sqrt{k},v\times \sqrt{k^3}$$$$v\times k\Rightarrow l\times \sqrt[3]{k},a\times \sqrt[3]{k^2}$$

Commented by Tawa1 last updated on 19/Oct/18

$$\mathrm{Am}\mathrm{trying}\mathrm{to}\mathrm{study}\mathrm{it}$$

Commented by Tawa1 last updated on 19/Oct/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}\mathrm{but}\mathrm{i}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{get}\mathrm{it}.$$

Commented by Tawa1 last updated on 19/Oct/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

Commented by MJS last updated on 19/Oct/18

$$\mathrm{square}$$$$\mathrm{side}=a\Rightarrow \mathrm{area}=a^2$$$$\mathrm{side}=k\times a\Rightarrow \mathrm{area}={\left(k\times a\right)}^2=k^2\times a^2$$$$\mathrm{same}\mathrm{for}\mathrm{triangle}$$$$\mathrm{side}=a;\mathrm{height}=h_a\Rightarrow \mathrm{area}=\frac{a\times h_a}{2}$$$$\mathrm{side}=k\times a;\mathrm{height}=k\times h_a\Rightarrow \mathrm{area}=\frac{\left(k\times a\right)\times \left(k\times h_a\right)}{2}=k^2\times \frac{a\times h_a}{2}$$$$\mathrm{same}\mathrm{for}\mathrm{circle}$$$$\mathrm{radius}=r\Rightarrow \mathrm{area}=\pi r^2$$$$\mathrm{radius}=k\times r\Rightarrow \mathrm{area}=\pi {\left(k\times r\right)}^2=k^2\pi r^2$$$$$$$$\mathrm{similar}\mathrm{for}\mathrm{volumes}$$

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