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Question Number 46083 by peter frank last updated on 20/Oct/18

Answered by tanmay.chaudhury50@gmail.com last updated on 21/Oct/18

$${\alpha }^7=1$$$${\alpha }^7-1=0$$$$(\alpha -1)({\alpha }^6+{\alpha }^5+{\alpha }^4+{\alpha }^3+{\alpha }^2+\alpha +1)=0$$$$$$$$whenA\times B=0$$$$eitherA=0orB=0$$$$hence{\alpha }^6+{\alpha }^5+{\alpha }^4+{\alpha }^3+{\alpha }^2+\alpha +1=0$$

Commented by peter frank last updated on 21/Oct/18

$$\mathrm{thanks}$$

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