Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 46121 by Sanjarbek last updated on 21/Oct/18

Commented by tanmay.chaudhury50@gmail.com last updated on 21/Oct/18

$$asx\to \mathrm{\infty }so{2}^x\to \mathrm{\infty }$$$$hence{3}^{2^x}\to \mathrm{\infty }$$$$sofinally$$$$(3^{2^x}-2)\to \mathrm{\infty }$$$$\underset{x\to \mathrm{\infty }}{\lim }(3^{2^x}-2)=\mathrm{\infty }$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com