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Question Number 46378 by rahul 19 last updated on 24/Oct/18

Factorise :  3x^4 +6x^3 +8x^2 −2x−3=0.

Factorise:3x4+6x3+8x22x3=0.

Answered by MJS last updated on 24/Oct/18

factor 1 =3  x^4 +2x^3 +(8/3)x^2 −(2/3)x−1=0  (x^2 +ax+b)(x^2 +cx+d)=0  by comparing the constants we get 4 equations  (1)  a+c−2=0  (2)  ac+b+d−(8/3)=0  (3)  ad+bc+(2/3)=0  (4)  bd+1=0  solving (1) for a, (2) for b, (3) for d we get  (4)  9c^6 −54c^5 +156c^4 −364c^3 +280c^2 −176c=0  ⇒ c=0, a=2, b=3, d=−(1/3)  so we have  3(x^2 +2x+3)(x^2 −(1/3))=0  solving the square factors we get  3(x+1−i(√2))(x+1+i(√2))(x−((√3)/3))(x+((√3)/3))=0

factor1=3x4+2x3+83x223x1=0(x2+ax+b)(x2+cx+d)=0bycomparingtheconstantsweget4equations(1)a+c2=0(2)ac+b+d83=0(3)ad+bc+23=0(4)bd+1=0solving(1)fora,(2)forb,(3)fordweget(4)9c654c5+156c4364c3+280c2176c=0c=0,a=2,b=3,d=13sowehave3(x2+2x+3)(x213)=0solvingthesquarefactorsweget3(x+1i2)(x+1+i2)(x33)(x+33)=0

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