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Question Number 46563 by Necxx last updated on 28/Oct/18
limx→0(ax+bx+cx3)1/x
Answered by ajfour last updated on 28/Oct/18
limx→0(1+ax−1+bx−1+cx−13)1/x=limx→0{[1+f(a,b,c,x)]1f(a,b,c,x)}f(a,b,c,x)x=elna+lnb+lnc3=(abc)1/3.
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