If in triangle ABC ((cosB)/b) =((cosC)/c), show that the triangle is isosceles


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Question Number 46570 by scientist last updated on 28/Oct/18

$I f i n t r i a n g l e A B C \frac{c o s B}{b} = \frac{c o s C}{c}, s h o w t h a t t h e$ $t r i a n g l e i s i s o s c e l e s$
	Answered by tanmay.chaudhury50@gmail.com last updated on 28/Oct/18

	$\frac{s i n A}{a} = \frac{s i n B}{b} = \frac{s i n C}{c}$ $\frac{c o s B}{c o s C} = \frac{s i n B}{s i n C} = \frac{b}{c}$ $s i n B c o s C - s i n C c o s B = 0$ $s i n (B - C) = 0 s o B - C = 0$ $∠ B = ∠ C p r o v e d$
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