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Question Number 46636 by azharkhan250963@gmail.com last updated on 29/Oct/18

$$\tan \theta ={10\tan 60}^{°}$$

Answered by tanmay.chaudhury50@gmail.com last updated on 29/Oct/18

$$tan\theta =10\times \sqrt{3}$$$$tan\theta =10\times 1.732$$$$\theta ={tan}^{-1}(17.32)$$

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