1≤n,m∈N. Prove that 3(m+n)+10ln (m!n!)≥6(√(mnH_m H_n )). (H_m =Σ_(i=1) ^m (1/i), H_n =Σ


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Question Number 46640 by canhtoan last updated on 29/Oct/18

$1 ⩽ n, m \in N . P r o v e t h a t$ $3 (m + n) + 10 \ln (m! n!) ⩾ 6 \sqrt{{m n H}_{m} H_{n}} .$ $(H_{m} = \underset{i = 1}{\sum^{m}} \frac{1}{i}, H_{n} = \underset{j = 1}{\sum^{n}} \frac{1}{j})$
Commented by canhtoan last updated on 29/Oct/18

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