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Question Number 46657 by Necxx last updated on 29/Oct/18
integrtesin−1x
Answered by tanmay.chaudhury50@gmail.com last updated on 29/Oct/18
∫sin−1xsin−1x×∫dx−∫[dsin−1xdx∫dx]dxxsin−1x−∫x1−x2dxt2=1−x22tdt=−2xdxso∫xdx1−x2∫−tdtt.=−t=−1−x2ansisxsin−1x+1−x2
Commented by Necxx last updated on 29/Oct/18
thanksboss
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