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Question Number 46681 by Aditya789 last updated on 30/Oct/18

Commented by math1967 last updated on 30/Oct/18

$$isitsolve?$$

Commented by Aditya789 last updated on 30/Oct/18

$$\mathrm{yes}$$

Answered by tanmay.chaudhury50@gmail.com last updated on 30/Oct/18

$$\frac{x-b-c}{a}-1+\frac{x-c-a}{b}-1+\frac{x-a-b(\leftarrow shouldbe)}{c}-1=0$$$$\frac{x-a-b-c}{a}+\frac{x-a-b-c}{b}+\frac{x-a-b-c}{c}=0$$$$(x-a-b-c)(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=0$$$$sox-a-b-c=0$$$$x=a+b+c$$$$\frac{1}{a}+\frac{1}{b}+\frac{1}{c}cannotbeequalstozero$$$$$$

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