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Question Number 46713 by agniv last updated on 30/Oct/18

((x−1)/(x−2))−((x−2)/(x−3))=((x−5)/(x−6))−((x−6)/(x−7)) solve for x

x−1x−2−x−2x−3=x−5x−6−x−6x−7solveforx

Answered by Kunal12588 last updated on 30/Oct/18

(((x−1)(x−3)−(x−2)^2 )/((x−2)(x−3)))=(((x−5)(x−7)−(x−6)^2 )/((x−6)(x−7))) ((x^2 −4x+3−x^2 −4+4x)/(x^2 −5x+6))=((x^2 −12x+35−x^2 −36+12x)/(x^2 −13x+42)) ((−1)/(x^2 −5x+6))=((−1)/(x^2 −13x+42)) x^2 −5x+6=x^2 −13x+42 8x=36 x=(9/2)=4.5

(x−1)(x−3)−(x−2)2(x−2)(x−3)=(x−5)(x−7)−(x−6)2(x−6)(x−7)x2−4x+3−x2−4+4xx2−5x+6=x2−12x+35−x2−36+12xx2−13x+42−1x2−5x+6=−1x2−13x+42x2−5x+6=x2−13x+428x=36x=92=4.5

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