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Question Number 46751 by Joel578 last updated on 31/Oct/18

$$\mathrm{Prove}\mathrm{that}\mathrm{there}\mathrm{exist}4\mathrm{distinct}\mathrm{positive}\mathrm{integers}$$$$\mathrm{such}\mathrm{that}\mathrm{each}\mathrm{integer}\mathrm{divides}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{the}$$$$\mathrm{remaining}\mathrm{integers}.$$

Commented by MrW3 last updated on 31/Oct/18

$$n,2n,3n,6nwithn\in \mathbb{N}$$

Commented by Joel578 last updated on 31/Oct/18

$$\mathrm{please}\mathrm{explain}\mathrm{how}\mathrm{to}\mathrm{get}\mathrm{those}\mathrm{numbers},\mathrm{Sir}$$

Commented by MrW3 last updated on 31/Oct/18

$$tryandsee.$$$$Ithinkthereexistmanyothernumberswhich$$$$alsofulfillthecondiction,e.g.$$$$n,4n,5n,10n.$$

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