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Question Number 46977 by 23kpratik last updated on 03/Nov/18
3x+2≡0(mod7)
Commented by maxmathsup by imad last updated on 03/Nov/18
3x+2=7kletconsiderthecongruencemodulo3⇒3.x+2.=7.k⇒−1.=k.⇒k=3p−1⇒3x+2=7(3p−1)⇒3x+2=21p−7⇒3x=21p−9⇒x=7p−3.
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